Position: Index > 555 Circuit >

9VDC to 5 VDC circuit diagram using 555 timer IC (74OL6010)

2015-02-02 21:21  
Declaration:We aim to transmit more information by carrying articles . We will delete it soon, if we are involved in the problems of article content ,copyright or other problems.

This article describes the 9VDC to 5 VDC circuit diagram using 555 timer IC (74OL6010). The content is very simple, very helpful. Components in this article can help you understand better understanding of this article. For example, in this article, you can go to find and buy these components:74OL6010.

This following circuit diagram is used to convert 9VDC to 5VDC using 555 timer IC. A 555 timer can be used to generate a squarewave to produce a negative voltage relative to the negative battery terminal. When the timer output at pin 3 goes positive, the series 22 uF capacitor charges through the diode (D1) to about 8 volts. When the output switches to ground, the 22 uF cap discharges through the second diode (D2) and charges the 100 uF capacitor to a negative voltage. The negative voltage can rise over several cycles to about -7 volts but is limited by the 5.1 volt zener diode which serves as a regulator. Circuit draws about 6 milliamps from the battery without the zener diode connected and about 18 milliamps connected. Output current available for the load is about 12 milliamps. An additional 5.1 volt zener and 330 ohm resistor could be used to regulate the 9 down to 5 at 12 mA if a symmetrical /- 5 volt supply is needed. The battery drain would then be around 30 mA.

 

5v-to-9v-diagram

 


Reprinted Url Of This Article:
http://wiringdiagramcircuit.com/9vdc-to-5-vdc-circuit-diagram-using-555-timer-ic/