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Power amplifier 170W

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Power Amplifier 170W

Power_amp_170W.gif (23589 bytes)

    ??? ?????? ???????? ????? ???? ??????? ??????? ?????????. ? ??????? ??? ?? ??? ????????? ?????????? ??? ????????????? ????????? ???????? ???? ?????? ????, ????? ??? ????? ? ????????? ???????????? ??? ???????????? ?? ??5534, ???? ?????? ???. ???? ?????? ?? ???????????? ??? ????? ???? ???????????, ??? ?15V, ??? ?????????? ?? IC1. ???? ??????? ?? ??? ??????? ??? R7,9 ??? ??? ?????? Zener D1,2. ???? ?????? ??????? ??? ?????? ????????? ?????? C1-R3 ??? ??? ?????????? R2-C2, ?? ?????????? ?? ???????????? ?? ????? ?????????? ??? ???????? ???????, ?? ??? ???????????? ???????. ? ?????????? ????????? IC1 ?????????? ??? ?????????? ?????????, ??? ?????? ? ?? ???????????? ??????? ( ), ?????????? ??? ????????? ?????? ??? ????????? ?????????. ? ???? ????????? ??? ??? ?????, ??????????? ???? ????? R4-R5, ???? ??? R6. ? ???????????? ??????? ??? ???? ???????? C4, C5 ??? C12, ??? ?? ?????? ??????????? ??? ??? ??????????? R6, R5, ???? ??? R6 (?40). ?? ?????????? Q1, Q2 ??????????? ?? ???? ? ??? ?? ????? ??? ??????? ??? ???? ???? ????? 10mA, (??????????? ??? ??? ??????????? R10,14). ???? ????? ???????? ?? ?????????? ?????? Q8,9,10,11 ?? ????? ?????????? ?? ???? ??, (?????????? ??? ?? ?????????? Q3 ??? ?? ??????? ?R1, ?? ????? ??????? 100mA, ??? ???? ??? ?????????? ?????? ???? ?????, ??? ??????????? ?? ????? ????? 27mV, ????? ???? ??????????? R25,26,27,28). ??? ?? ????????? ??? ??????? ?????? ??????? ???????????, ?????? ?? ?????????? Q1,2,3,6,7 ?? ???????????? ????? ???? ?????? ???? ?? ?? ?????????? ??????. ?? ?????? D9-10 ???????????? ??? ??????? ?????? ??? ?????????? ?????? , ??? ?????? ?? ????????????? ??? ?? ??????. ? R29 ??? ? C18, ??????????? ??? ???????? ???????? Boucherot, ?? ????? ????????? ??? ??????????? ???? ?????? ??????????. ?? ????? L1, (??????????? ??? 15 ??????? ????? ????????? 1mm), ??????????? ??? ????? ??? ???????? ??? ????? ??????????, ???? ??????? ????????? ???????. ? R30, ??????????? ??? ?? ???????????? (???? ??????), ???????? ???????????? ??????. ? ????????? ??? ???????? ??? ??????????? ????????? ??? ??????? ??? ???? ?????? ????? ???? ?????. ?????? ??? ?????? ?? ?????????, ????? ? ???? ???? ??? ?????????? ??????, ?? ??? ???? ??????, ?????? ??????????, ? ????? ??????? ?? ????????? ??????? ??? ??? Fan, ???? ??? ? ??????????? ????????? ??????, ???? ? ????????? ???????? ?? ????? ????, ??? ?????? ??????? ???????? ??? ?? ?????? ?????? ????? ??? 4 ohms. O ????????? ?? ????????? ??? ???????????, ??? ??? ???? ??????. ???? ????? ?? ????????????? ??? ????? ??? ????????, ?? ??? ??????? ??????????, ??? ???? ??? ???? ???? ?????? ???. ?? ?????? ????? ??? ??????? ???????? ???????????? ??? ????????? Elektor ???? 12/95.

   In the drawing he appear simple but powerful power amplifier. His difference with the classic designings, that use differential amplifier in their input, they are that this amplifier it uses a completed the NE5534, in his input. Thus it should we degrade the high voltage of power supply, in ?15V, that needs the IC1. This becomes with the help of R7,9 and Diodes Zener D1,2. In the input exist a High-pass filter C1-R3 and low-pass filter R2-C2, so that is limited the bandwidth of frequencies of unit of entry, in a concrete bandwidth. The IC1 function as differential amplifier, which the not inverting input ( ), work as central node of total feedback. The voltage of feedback from the exit, is applied in the node R4-,R5, via the R6. The compensatory becomes from capacitors C4, C5 and C12, while the gain is appoint by resistors R6, R5, via R6 (X40). Transistors Q1, Q2 works in Class A and the current that elapse from in them is 10mA, (is determined by resistors R10,14). In the exit exist the power transistors Q8,9,10,11 which work in Class AB, (is regulated by transistor Q3 and the trimmer TR1, in current of calm 100mA, for each one power transistor in the exit, that correspond in fall of voltage 27mV, above in resistors R25,26,27,28). In order to we achieve the biggest possible thermic stability, should transistors Q1,2,3,6,7 be placed above in heatsink, with the power transistors. The diodes D9-10 protect the output stage, from reverse voltages, that can be created from the load. The R29 and the C18, shape one classic network of Boucherot, which improve the stability in the high frequencies. The inductor L1, (is constituted by 15 coils wire of diameter 1mm), protect the exit of amplifier from problems, because existence of capacitive load. The R30, ensure the not questioning (because inductor), passage of square pulses. The build of amplifier does not present difficultie for somebody that has a certain experience in the sector. What it should you are careful, is the good refrigeration of power transistors, with one good heatsink, capable dimensions, which probably it needs help from one Fan, because the temperature goes up enough, when the amplifier work in complete power, for big time distance and with low load near in the 4 ohms. The amplifier will need two power supply, one for each channel. Good it is we protect the exit of amplifier, with a circuit of protection, from what I give in my page. The drawing of this power amplifier, was published in the magazine Elektor 12/95.

DC Protection and Delay 1

System Protection 2  [English]

System Protection 2 [Greek]

Part List

R1=68KohmC1=2.2uF 100V MKTQ2=MJE340
R2=2.2KohmC2=1nF 100V MKTQ3=BD139
R3-6=22KohmC3-8-9-10-11-14-15=100NFQ4=BC546B
R4-22-23=1KohmC4=33pF 160V  polystyreneQ5=BC556B
R5-8-10-14=560 ohmC5=47pF  160V polystyreneQ6=MJE15030
R7-9=3.3Kohm5WC6-7=100uF  63VQ7=MJE15031
R11-15=150 ohmC12=470pF  160V polystyreneQ8-9=MJ15003
R12-13=15KohmC13=680nF 100V MKTQ10-11=MJ15004
R16=680 ohmC16-17=150nF 100V MKTD1-2=15V 1.5W Z
R17=180 ohmC18=33nF 250V MKTD3-4=BAT85
R18-19=10 ohmC19-20=100uF 100VD5-6-7-8=1N4004
R20-21=27KohmL1= See textD9-10=BY254
R24=56 ohmF1-2=6.3AT FUSE
R25-26-27-28=0.27 ohm/ 5WTR1=250 ohms  TRIM
R29=10 ohm/  5WIC1=NE5534
R30=2.2  ohm/5WQ1=MJE350

.

SPECIFICATIONS

Input sensitivity1 Vrms
Input impedance17.8 Kohm
Output Power  (0.1% THD)164Watt -8 ohms      275Watt- 4 ohms
Slew Rate20V/?s
Signal to Noise ratio>96dB
THD<0.004% (1KHZ) in 1 Watt -8ohms and <0.05% (20HZ-20KHZ) 
IMD (50HZ : 1KHZ   4:1)<0.003% in 1Watt 8ohms  and <0.0035% in 100Watt 8ohms
DAMPING FACTOR (in 8ohm)>345 in 1KHZ and <275 in 20KHZ

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Power Supply For P.A 170W

SUPPLY_FOR_POWER_AMP.gif (15026 bytes)

   ??? ??? ???????? ?????? ?????? ?? ?????????????? ?? ?????? ??????????? ??? ????????? ??????, ??? ??????? ????. ???? ??? ?????? ??? ???????? ?? ??????????? ?????? ?? ???? ??? ???? ??????? ???? ??? ?????? ???????????? ????????. ??? ???? ?????? ???????? ??????????? ??? ???? ??????????????? . ???? ?????? ??? ??????????????? ??? ???? ?????? AC, ?????? ?? ???????????? ?? ??????? ???????????? ????????????? ?????????? 1, ???? ? ?????????? ??????? ?? ??????? ?????. ?? ??????? ??? ?? ???????????????? ?????? ?? ????? ????????? ,???? ?? ?????????? ??? ?????? ??? ?? ??????? ??? ?????????? ? ?????????.

  For the power amplifier, it can be used the general power supply for power amplifiers, that usually I give. Because the power of amplifier the supply it should it has also this proportional power and big capacity of capacitors. For each power amplifier correspond also a transformer. In the entry of transformers and in line AC, can be adapted the circuit of delay ofcircuit protection 1, in order that the supply of network become softly. The cables that we will use should be suitable, so that they transport the voltages and the currents, that need the amplifier.

Part List

T1=110-240V@ 2X42.5V  650VA

                  @[2X15V 1A*]

BR1-3=400V 35A BRIDGEC5-8=2200uF 25V
BR2=200V 3A BRIDGEC6-9=100nF 100V
T2=110-240V@ 2X42.5V   650VAC1-2-3-4=10000 uF 100VC7-10=47uF 25V
F1=3.15 AT FUSEC11-12-13-14=10000 uF 100VC15=33nF 630V
RX-CX-RL1S1= SWITCH 2X2 10A

 

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