# Wheatstone Bridge Circuit

AWheatstone bridgeis used to calculate an unknown resistance with the help of a bridge circuit. For this, the two legs of the bridge circuit are kept balanced and one leg of it includes the unknown resistance. The Wheatstone bridge principle is similar to the working of potentiometer. Slight modifications in the Wheatstone bridge can help in finding other quantities like capacitance and inductance as well. It also helps in finding the amount of a particular gas that is mixed among a sample. The Wheatstone bridge measurement is very accurate and the value of the unknown resistance is mostly found out in order to measure other physical values like temperature, force, pressure and so on. It can be used in all electronic circuits. The device was first invented by Samuel Hunter Christie in 1833. The concept was later modified and popularized by Sir Charles Wheatstone in the year 1843.

TAKE A LOOK :POTENTIOMETER

### Wheatstone Bridge Measurement

#### Balanced Condition

As shown in the circuit diagram, there are four resistances connected as a bridge circuit. The three resistors R1, R2 and R3 will have known values. The value of the resistance RXwill be unknown and has to be calculated. The value of resistance R2 is adjustable. A galvanometer has to be set between the points B and D.

TAKE A LOOK :GALVANOMETERS

The condition to be satisfied at the point of balance is given below.

If R2/R1 = RX/R3, then VBD= 0 and current through VG= 0. To reach this condition, the adjustable resistor is varied. The direction of the current can be known from the value of the resistor R2.

As soon as the balance condition is obtained the value of the resistance RXis obtained.

Thus, RX =[R2/R1] x R3

This method is very accurate as the other values of resistors are of high precision.

#### Unbalanced condition

If the value of the resistors R1, R2 and R3 are fixed, then the value of the unknown resistor RXhas to be found out with the help of Kirchhoff’s voltage and current laws. For this, the bridge circuit will produce a voltage as well as a current as the circuit will not be balanced. This is the process mostly used in the measurement of strain gauges and resistance thermometers. This method is much easier to use as calculations can be done more easily with a voltage and current value than trying to make the circuit balanced.

To calculate the currents between the junctions B and D use Kirchhoff’s current law.

I3 – IXIG= 0

I1 – I2 – IG= 0

This can be further simplified as

I3 = IXand I1 = I2…………………………………..[1]

To calculate the voltage in the loops ABD and BCD use Kirchhoff’s voltage law.

[I3 R3] – [IGRG] – [I1 R1] = 0

[IXRX] – [I2 R2] [IGRG] = 0

On re-arranging the above equations we get the value of unknown resistance as

RX= [R2 I2 R3 I3]/ [R1 I1 IX]…………………..[2]

Substituting value of[1]in[2]

RX= [R3 R2]/ R1.

There may be cases when the values of all the resistors are known. ?If so, the value of the voltage between B and D [VG] can be found out from the following equation.

VG= VS* ([R3 /{R3 RX}] – [R2/{R1 R2}])

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