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FLIP_FLOP_INDEPENDENT_LAMP_DRIVER

2016-08-04 16:58  
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FLIP_FLOP_INDEPENDENT_LAMP_DRIVER
Assume first that SCRt is on and SCR2 is off so that C1 is fully charged, with its LMP2 end positive. The state of the circuit can be changed by pressing S2. As SCR2 turns on, it turns SCR1 off capacitively via its anode. Capacitor C1 then recharges in the opposite manner (i.e., the left end is now positive). The state of the circuit can be changed again by pressing S1, thus driving SCR1 on by way of its gate, and driving SCR2 off capacitively via its anode.