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# How to build 0-50V 2A Bench power supply

2015-03-20 20:26
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## Circuit diagram

I use the lm10 IC because it has a reference voltage and that’s useful for dc power supply. With two ICs can take different output voltage and amperage. This circuit is protected from short circuit.P2 is for controlling the current at the range of 0-2A. Stabilize the output voltage with R4 on negative pin on op-amp and with R2 & P1 on positive pin.

Op-amp output controls T1 that not let ripple of voltage.T1 increase or decrease ampere of R6 and control the voltage of T5 & T4. Pin 1 is the reference voltage and reference voltage is losing some voltage on R1 that has 100uA . This current passes through P1 too. Vlose p1=100uA*Rp1 This lose voltage regulate output voltage rate of output current is compare between reference voltage of P3 and lose voltage on R11.T3 is protecting short circuit with R11. For reduce out put voltage to 0v should parallel one resistor 470 ohm in out put. Minimum voltage is 0.4v. The maximum output voltage is fixed with R1b and should not become over of 50v. Therefore your transformer should give 36V, 3A with 4700uF capacitor. T6, T5, T7 need heatsilk.

## Parts

R1a = 2,2 KR1b = read the textR2 = 10 KR3, R7 = 3.3 kR4 = 390 OhmR5 = 47 KR6 = 3.3 K 1WattR8 = 180 OhmR9, R10 = 0.47 Ohm 3WattR11 = 0.075 Ohm 2WattR12 = 470 OhmP1 = 500K liner potentiometerP2 = 4.7 K potentiometerP3 = 10 K potentiometerC1 = 1nFC2 = 10nFC3 = 22nFC4 = 47mF 63v electrolyticC5 = 4700mF 80v electrolyticT1, T2 = BC161T3, T4 = BD141T5 = BD241T6, T7 = 2V3055D1, D2 = 1N4148D3, D4 = 1N4001IC1, IC2 = LM10C

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