Position: Index > Power Supply Circuit >

Reducing L200 Power Dissipation (OPA842IDG4)

2015-03-22 18:47  
Declaration:We aim to transmit more information by carrying articles . We will delete it soon, if we are involved in the problems of article content ,copyright or other problems.

This article describes the Reducing L200 Power Dissipation (OPA842IDG4). The principle is very simple, very practical. The circuit components can help you understand better grasp this principle. For example, in this circuit, you can go to find and buy these components:OPA842IDG4.

It’s good to reduce the power dissipated by the device. Using resistor connected in series to the input (the left figure) is a simple and economic method to reduce the device input-output differential voltage. Here’s the formula for calculating R:

R= [Vi min- (Vo Vdrop)]/Io

Vdrop = minimum differential voltage between the input and the output of the device at current Io

Vin min = minimum voltage

Vo = Output voltage

Io = output current

Reducing L200 Power Dissipation using Series Resistor1 circuit schematic

Resistor R can be connected between pins 1 and 2 of the IC instead of in series with the input if the load is constant (the right figure). So, part of the load current flows through the device and part through the resistor. This configuration is available when the minimum current by the load is:

Io min = Vdrop/R



Reprinted Url Of This Article: